Differentiates composite functions
d/dx[f(g(x))] = f'(g(x))·g'(x)
Functions
Derivatives
d/dx[sin(x²)]
Outer: f(u)=sin(u), Inner: g(x)=x²
f'(u)=cos(u), g'(x)=2x
Result: cos(x²)·2x = 2x·cos(x²)
Physics
Engineering
Advanced calculus
Problem 1: d/dx[(x³+1)⁵]
Answer: 5(x³+1)⁴·3x²
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